2.1 Energy analysis of concrete damage and destruction
The first law of thermodynamics reflects the conservation of different forms of energy in the process of transfer and transformation, energy transformation is the essential feature of the physical change process of materials, and material damage is a state destabilization phenomenon driven by energy[20]. For concrete lining structures, energy is easily released along the direction of minimum compressive stress or tensile stress, and the change of energy during failure is analyzed by the stress-strain curve of concrete under uniaxial tests, as shown in Fig. 1.
From the energy point of view, the damage process of concrete under external load can be divided into three stages: the first stage is the energy accumulation stage (OA, Elastic stage), this stage is mainly for the external input energy and its internal elastic strain energy conversion process; the second stage is the energy dissipation stage (AB, Elastic-Plastic stage), this stage is mainly for the external input energy and strain energy and dissipation energy conversion process; the third stage is the energy release stage (BC, Failure stage), this stage is mainly for the release of elastic strain energy and concrete fragmentation surface energy and kinetic energy conversion process, resulting in the overall destruction of concrete.
Based on the above three stages, the energy corresponding to the different stages is calculated from the area of the zone enclosed by the stress-strain curve of concrete. The maximum energy that can be absorbed in the first stage is recorded as UOA, such as the area of the green area in Fig. 1, corresponding to the maximum stress σA; the maximum energy that can be absorbed in the second stage is recorded as UAB, the area of the yellow area in Fig. 1, corresponding to the maximum stress that is the peak stress σB. The energy calculation formula corresponding to the two stages is as follows (1) and (2).
$${U_{OA}}=\frac{1}{{2{E_0}}}\sigma _{A}^{2}\begin{array}{*{20}{c}} {}&{0<\varepsilon \leqslant {\varepsilon _A}} \end{array}$$
1
$${U_{AB}}=\int {\sigma d\varepsilon \begin{array}{*{20}{c}} {}&{{\varepsilon _A}<\varepsilon \leqslant {\varepsilon _B}} \end{array}}$$
2
In the formula: \({E_0}\) is the modulus of elasticity of concrete; \({\varepsilon _A}\) is the maximum strain of the elastic phase; \({\varepsilon _B}\) is the strain corresponding to the peak stress.
The maximum energy that can be absorbed without failure of the concrete is the sum of the energy accumulated in the first stage and the energy accumulated in the second stage, as in Eq. (3).
$${U_{OB}}={U_{OA}}+{U_{AB}}$$
3
In the equation: UOB is the maximum energy that can be absorbed without damage. When the input energy is less than UOA, the concrete material is considered to be in the elastic phase and no damage occurs; when the input energy is greater than UOA and less than UOB when the concrete material is considered to be steadily expanding internal micro-cracks leading to damage, accompanied by irrecoverable plastic deformation, causing loss of strength; when the input energy is greater than UOB when the concrete occurs as a whole failure.
For the case of concrete without failure, this study uses the releasable elastic strain energy of concrete to characterize the maximum amount of energy that can be absorbed by concrete without failure. Figure 2 shows the relationship between the dissipated energy and the releasable elastic strain energy in the unit, the gray area is the energy dissipated by the damage and plastic deformation of the unit, and the blue area is the maximum releasable elastic strain energy stored in the unit. When the elastic strain energy is less than the maximum releasable elastic strain energy stored in the unit, the mass point unit is not destroyed as a whole under the action of external forces.
2.2 Blasting vibration safety criteria
When the tunnel is blasted, most of the energy generated by tunnel blasting is consumed in the crushing of the rock at the palm face, and a small portion of the energy is propagated outward along the geotechnical body in the form of stress waves, which are gradually converted into elastic strain energy, damping energy and kinetic energy of the geotechnical body in the process of propagation. Stress waves cause vibration of geotechnical particles and existing tunnel structure, which may cause damage or destruction of the surrounding rock and existing structure, and explore the nature of the process of energy input, conversion and release. Using the vibration velocity time curve of concrete mass as shown in Fig. 3, the energy conversion process of forced vibration of mass unit is divided into three stages.
The first stage is the energy input stage
the stress wave generated by the blast is the energy input source, under the action of the stress wave, the mass unit is stressed to produce vibration acceleration, for a single cycle, in Δt1 time, with the increase in time the vibration speed gradually becomes larger (kinetic energy gradually increases), the resulting strain also gradually increases (elastic strain energy increases), until it reaches the peak vibration speed vmax (at this time the kinetic energy reaches the maximum, elastic strain energy is not the maximum), at this time the stress wave input energy reaches the maximum, the input energy conversion as shown in formula (4).
$$U={U_m}+U_{e}^{1}+{U_d}$$
4
In the equation: is the maximum energy of the stress wave input; \({U_m}\) is the maximum kinetic energy at the peak vibration speed; \(U_{e}^{1}\) is the elastic strain energy accumulated in the moment of Δt1; \({U_d}\) is the energy loss generated by the vibration of the mass unit.
The second stage is the energy conversion stage
in Δt2 time, the peak vibration speed is reached and then the vibration speed gradually decreases (kinetic energy gradually decreases), but the strain generated at this time will still increase (elastic strain energy continues to increase), until the kinetic energy in the cycle reaches the minimum value (the elastic strain energy reaches the maximum), the energy conversion process in this stage is the conversion of kinetic energy into elastic strain energy and dissipation energy, as shown in Eq. (5). Therefore, at the end of this phase, the elastic strain energy of the mass unit reaches its maximum value, as shown in Eq. (6).
$${U_m}=U_{e}^{2}+{U_d}$$
5
$$U_{e}^{{\hbox{max} }}=U_{e}^{1}+U_{e}^{2}$$
6
In the equation: \(U_{e}^{{\hbox{max} }}\) is the sum of the elastic strain energy accumulated in the moments Δt1 and Δt2; \(U_{e}^{2}\) is the elastic strain energy accumulated in the moment Δt2.
The third stage is the release of energy
the accumulated elastic strain energy is gradually released and converted into kinetic energy and dissipative energy. From the whole vibration process, the total energy input of stress wave is finally converted into dissipative energy and residual elastic strain energy.
Based on the energy principle of the concrete failure criterion, it is known that the failure of concrete is due to the accumulation of elastic strain energy reaching the limit value, as long as the calculation of the elastic strain energy when the decay of the peak vibration speed is the minimum value, the safety criterion of concrete failure under blasting vibration can be derived. Specific analysis: the slope of the rising and falling sections of the peak vibration speed is the acceleration of the mass vibration, and the difference between the duration of the rising and falling sections of the peak vibration speed is not large ( \(\Delta {t_1} \approx \Delta {t_2}\)), that is, the acceleration of the mass in the rising and falling sections of the peak vibration speed is the same size, according to Newton's second law of motion, the displacement produced by the rising and falling sections of the peak vibration speed is the same. According to Hooke's law, the elastic strain energy of the rising and falling sections of the peak vibration speed is the same, as in Eq. (7).
$$U_{{\text{e}}}^{1}{\text{=}}U_{{\text{e}}}^{2}$$
7
The elastic strain generated by the mass in the falling section can be converted to kinetic energy at the peak vibration speed, as in Eq. (8).
$$U_{{\text{e}}}^{2}{\text{=}}{U_m}=0.5\Delta mv_{{\hbox{max} }}^{2}$$
8
Therefore, the maximum elastic strain energy of the mass unit is twice the kinetic energy corresponding to the peak vibration speed, as shown in Eq. (9).
$$U_{{\text{e}}}^{{\hbox{max} }}{\text{=}}U_{{\text{e}}}^{1}+U_{{\text{e}}}^{2}=2 \times \frac{1}{2}\Delta mv_{{\hbox{max} }}^{2}=\Delta mv_{{\hbox{max} }}^{2}$$
9
Then, according to the energy principle described above, the existing tunnels are divided into the following two methods of calculating the safety criterion for blast vibration:
For existing tunnel lining structures, a certain amount of elastic strain energy has been accumulated after the end of construction, and the elastic strain energy that has been accumulated in the static state can be calculated according to the stress state of the structural unit, in the principal stress space, the calculation formula is as in Eq. (10):
$${U_{^{{\text{e}}}}}^{0}=\frac{1}{{2{E_0}}}[\sigma _{1}^{2}+\sigma _{2}^{2}+\sigma _{3}^{2} - 2\nu ({\sigma _1}{\sigma _2}+{\sigma _2}{\sigma _3}+{\sigma _1}{\sigma _3})]$$
10
In the equation: σ1, σ2, σ3 are the three principal stresses corresponding to the maximum strain energy of the rock unit; ν is the Poisson's ratio.
The existing tunnel structure does not produce damage to meet (11):
$$U_{{\text{e}}}^{{\hbox{max} }} \leqslant {U_{OA}} - U_{{\text{e}}}^{0}$$
11
Substitution of equations (1), (9) and (10) into Eq. (11) yields the vibration speed criterion for the existing tunnel structure without damage to any unit volume:
$${v_{\hbox{max} }} \leqslant \sqrt {\frac{1}{{2\rho {E_0}}}\sigma _{A}^{2} - \frac{1}{{2\rho {E_0}}}[\sigma _{1}^{2}+\sigma _{2}^{2}+\sigma _{3}^{2} - 2\nu ({\sigma _1}{\sigma _2}+{\sigma _2}{\sigma _3}+{\sigma _1}{\sigma _3})]}$$
12
In the inequality: ρ is the density. In the design of hard rock tunnels, the secondary lining is often used as a safety reserve, which is subjected to smaller forces, so the elastic strain energy already stored in the tunnel secondary lining under static force is less, and the elastic strain energy already accumulated in the secondary lining is ignored in the calculation. The Eq. (12) is simplified as:
$${v_{\hbox{max} }} \leqslant \frac{{\sigma _{A}^{2}}}{{\sqrt {2\rho {E_0}} }}$$
13
The existing tunnel structure does not fail to meet (14):
$$U_{{\text{e}}}^{{\hbox{max} }} \leqslant {U^e} - U_{e}^{0}$$
14
In the inequality equation: \({U^e}\) is the critical value of releasable elastic strain energy in tension. The releasable elastic strain energy of the tunnel lining concrete in compression is much greater than that in tension, and blasting damage in existing tunnels is often manifested in the form of cracks and tensile failure. The critical value of releasable elastic strain energy in tension is calculated as in Eq. (15).
$${U^e}=\frac{{\sigma _{t}^{2}}}{{2{E_0}}}$$
15
In the equation: \(\sigma _{t}^{{}}\) is the tensile strength of the concrete, which can be obtained by referring to the current code or by testing the value of this parameter. Substitution of equations (9), (10) and (15) into Eq. (14) yields the vibration speed criterion for existing tunnel structures without tensile failure to any unit volume.
$${v_{\hbox{max} }} \leqslant \sqrt {\frac{{\sigma _{t}^{2}}}{{2\rho {E_0}}} - \frac{1}{{2\rho {E_0}}}[\sigma _{1}^{2}+\sigma _{2}^{2}+\sigma _{3}^{2} - 2\nu ({\sigma _1}{\sigma _2}+{\sigma _2}{\sigma _3}+{\sigma _1}{\sigma _3})]}$$
16
The calculation ignores the elastic strain energy \(U_{{\text{e}}}^{0}\) that has accumulated in the secondary lining, and simplifies the Eq. (16) as follows:
$${v_{\hbox{max} }} \leqslant \frac{{{\sigma _t}}}{{\sqrt {2\rho {E_0}} }}$$
17